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3s^2-45s=1350
We move all terms to the left:
3s^2-45s-(1350)=0
a = 3; b = -45; c = -1350;
Δ = b2-4ac
Δ = -452-4·3·(-1350)
Δ = 18225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18225}=135$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-135}{2*3}=\frac{-90}{6} =-15 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+135}{2*3}=\frac{180}{6} =30 $
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